It doesn't. Maybe check the problem to see if it's written differently? Otherwise, this equality is false. We can solve for x, however, and we get that x = sqrt15/4 for this equation. Take the …

Let's substitute for #sin (2x)#. This will give us: #cos (2x) cos (x) + (2sin (x)cos (x))* sin (x)# #=cos (2x)cos (x)+2sin^2 (x)cos (x)# Now, let's substitute #sin^2 ...

Please see the explanation below The equation is cos^3x+cos^2x-4cos^2 (x/2)=0 Let u=x/2 cos^3 2u+cos^2 2u-4cos^2 (u)=0 But cos2u=2cos^2u-1 Therefore, (2cos^2u-1)^3 ...

Feb 25, 2018 · dy/dx= (cos (x+y)-cos (y))/ (-xsin (y)-cos (x+y)) Differentiate both sides with respect to x. This means that every time we differentiate a term containing y, we ...

Find all values of #x# in # [0^circ, 360^circ)# to satisfy this equation? #sin x + sqrt3= 3 sqrt3 cos x#

As proved below. tan^2 x (cos^2x + 1) + cos^2 x = sec^2 x color (red) (tan x = (sin x / cos x), identity.

Dec 10, 2015 · Show that integration of cos^4 x sin² x dx = 1/16 [ x - (sin4x)/4 + (sin^3 2x)/3 ] +c ?

Substitute #cos (2x) = 2cos^2 (x)-1# Use the quadratic formula on the resulting equation.

Note: to differentiate #h (x)# we need to use the power and chain rule #h' (x) = 2 (cosx)^ (2-1)* 1 (-sin x)# #color (red) (h' (x) = -2sinx cos x)#

Oct 16, 2016 · This can be derived from the first limit shown above by using some algebraic manipulation to show that # (cos (x)-1)/x = - (sin (x)/x) (sin (x)/ (1+cos (x)))# and using the …